-4.9x^2+6.448=1.19

Solution for -4.9x^2+6.448=1.19 equation:

-4.9x^2+6.448=1.19

We move all terms to the left:

-4.9x^2+6.448-(1.19)=0

We add all the numbers together, and all the variables

-4.9x^2+5.258=0

a = -4.9; b = 0; c = +5.258;
Δ = b2-4ac
Δ = 02-4·(-4.9)·5.258
Δ = 103.0568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{103.0568}}{2*-4.9}=\frac{0-\sqrt{103.0568}}{-9.8}
=-\frac{\sqrt{}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{103.0568}}{2*-4.9}=\frac{0+\sqrt{103.0568}}{-9.8}
=\frac{\sqrt{}}{-9.8}
$